b^2+3b=40

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Solution for b^2+3b=40 equation:


Simplifying
b2 + 3b = 40

Reorder the terms:
3b + b2 = 40

Solving
3b + b2 = 40

Solving for variable 'b'.

Reorder the terms:
-40 + 3b + b2 = 40 + -40

Combine like terms: 40 + -40 = 0
-40 + 3b + b2 = 0

Factor a trinomial.
(-8 + -1b)(5 + -1b) = 0

Subproblem 1

Set the factor '(-8 + -1b)' equal to zero and attempt to solve: Simplifying -8 + -1b = 0 Solving -8 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '8' to each side of the equation. -8 + 8 + -1b = 0 + 8 Combine like terms: -8 + 8 = 0 0 + -1b = 0 + 8 -1b = 0 + 8 Combine like terms: 0 + 8 = 8 -1b = 8 Divide each side by '-1'. b = -8 Simplifying b = -8

Subproblem 2

Set the factor '(5 + -1b)' equal to zero and attempt to solve: Simplifying 5 + -1b = 0 Solving 5 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1b = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1b = 0 + -5 -1b = 0 + -5 Combine like terms: 0 + -5 = -5 -1b = -5 Divide each side by '-1'. b = 5 Simplifying b = 5

Solution

b = {-8, 5}

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